A company claims that out of 106 passengers the mean temperature is 98.2 with a st dev of .62. If the population mean is found to be 98.6. The company claims there is no difference between the mean temperatures. Alpha = .05
N=106, sample mean = 98.2, SAMPLE st dev = .62, mu = 98.6
1. PARAMETER OF INTEREST: Focused on whether the mu value is equal to the mean
2. CHOICE OF TEST: one sample, n=106 large sample = good, two-tailed, st. dev.
3. CHECK OF ASSUMPTIONS: n=106, st. dev. = .62
4. NULL HYPOTHESIS: There is no difference between the population mean and the sample mean.
5. ALTERNATIVE HYPOTHESIS: There is a difference between the population mean and the sample mean.
6. PROBABILITY STATEMENT: alpha = .05, therefore if p is less than alpha we reject the null.
7. TEST STATISTIC: 98.2 – 98.6 / (.62/sq root of 106)= -6.64, df 105
8. LEVEL OF SIGNIFICANCE: compare the area under the curb to the alpha and p value.
9. P VALUE: alpha = .05, p = less than .01therefore we fail to reject the null
10. RECOMMENDED DECISIONS: Based on the evidence there is sufficient data to reject the claim
11. INTERPRETATION: There is sufficient evidence at the 5% level of significance to reject the claim that body temperature is 98.6.
ONE SAMPLE T-TEST
